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9 June, 06:29

Write the expression as a single logarithm Log7X+log7Y-log7Z

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  1. 9 June, 06:48
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    For this, simply use the rules of logs:

    - Adding logs of the same base (which is 7 here) is the same as multiplying

    -Subtracting logs of the same base is dividing

    So the single log would be:

    log₇ (x*y/z) which is the same as

    log₇ (xy/z)
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