What value should be added to both sides of the equation X2 + 12 X + 6 equals - 5 to solve the question by completing the square

X^2 + 12x + 6 = - 5

x^2 + 12x = - 5 - 6

x^2 + 12x = - 11

x^2 + 12x + 36 = - 11 + 36 ... u add 36 to both sides <=

(x + 6) ^2 = 25

x + 6 = (+-) sqrt 25

x + 6 = (+-) 5

x = - 6 (+-) 5

x = - 6 + 5

x = - 1

x = - 6 - 5

x = - 11

solutions are : x = - 1 or x = - 11

ur answer : add 36 to both sides ... ur x term is 12, take half of ur x term, which gives u 6, then u square it, which gives u 36 ... and add that to both sides