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2 September, 03:27

How do you find the solutions of the equation 2sin^2 (x) = 1

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  1. 2 September, 03:34
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    Solve for x:

    2 sin^2 (x) = 1

    Divide both sides by 2:

    sin^2 (x) = 1/2

    Take the square root of both sides:

    sin (x) = 1/sqrt (2) or sin (x) = - 1/sqrt (2)

    Take the inverse sine of both sides:

    x = 2 π n_1 + (3 π) / 4 for n_1 element Z or x = 2 π n_2 + π/4 for n_2 element Z or sin (x) = - 1/sqrt (2)

    Take the inverse sine of both sides:

    Answer: x = 2 π n_1 + (3 π) / 4 for n_1 element Z or x = 2 π n_2 + π/4 for n_2 element Z or x = 2 π n_3 + (5 π) / 4 for n_3 element Z or x = 2 π n_4 + (7 π) / 4 for n_4 element Z
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