Ask Question
25 December, 21:15

A cube with 40-cm-long sides is sitting on the bottom of an aquarium in which the water is one meter deep. (Round your answers to the nearest whole number. Use 9.8 m/s^2 for the acceleration due to gravity. Recall that the weight density of water is 1000 kg/m^3.)

+3
Answers (1)
  1. 25 December, 21:35
    0
    940.8 N

    1254.4 N

    Step-by-step explanation:

    I would think the questions would be to calculate the forces at the top of the cube and at the sides. Thus:

    On the top:

    F = pressure * area

    P = density * gravity * height

    the height would be:

    1m - 0.4m = 0.6m

    replacing:

    P = 1000 * 9.8 * 0.6 = 5880

    A = (0.4) ^ 2 = 0.16

    F = 5880 * 0.16

    F = 940.8 N

    On the sides:

    dF = d * g * h * dA

    dA = 0.4 * dh replacing

    dF = 1000 * 9.8 * h * 0.4 * dh

    dF = 3920 * h * dh

    We integrate both sides and we have:

    F = 3920 * (h ^ 2/2), h = 0.6 up to h = 1

    F = (3920/2) * (1 ^ 2 - 0.6 ^ 2)

    F = 1254.4 N
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A cube with 40-cm-long sides is sitting on the bottom of an aquarium in which the water is one meter deep. (Round your answers to the ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers