A sequence is defined recursively using the equation. If f (1) = 100, what is f (6) ?

Step-by-step explanation:

The complete question is:

A sequence is defined recursively using the equation f (n + 1) = f (n) - 8. If f (1) = 100, what is f (6) ?

Since, A sequence is defined recursively using the equation f (n + 1) = f (n) - 8. If f (1) = 100, we have to find the value of f (6).

Consider

f (n+1) = f (n) - 8

Let n = 1, we get

f (1+1) = f (2) = f (1) - 8 = 100-8 = 92

Let n = 2, we get

f (2+1) = f (3) = f (2) - 8 = 92-8 = 84

Let n = 3, we get

f (3+1) = f (4) = f (3) - 8 = 84 - 8 = 76

Let n = 4, we get

f (4+1) = f (5) = f (4) - 8 = 76 - 8 = 68

Let n = 5, we get

f (5+1) = f (6) = f (5) - 8 = 68-8 = 60

Therefore, the value of f (6) is 60.