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16 July, 10:42

1. If ƒ (x) = 2x^2 + 3, find ƒ (3).

2. Simplify.

(x 3) ^4 • x^-3

3. Simplify.

8 - 3 (4 - 2x)

4.

If ƒ (x) = 4x - 3, what is ƒ (x) ^-1?

5.

if ƒ = { (2, 5), (3, 2) (4, 6), (5, 1), (7, 2) }, then ƒ is a function.

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Answers (1)
  1. 16 July, 10:51
    0
    1. f (3) = 2 (3^2) + 3 = 21

    2. Do you mean (x+3) ^4 X x^-3?

    3. 8-12+6x = 6x-4

    4. (4x-3) ^-1 = 1 / (4x-3)

    5. So whats the question for 5?
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