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15 January, 08:51

y=2x^2/3x^2-16 what is the horizontal asymptote for the above function? round to the nearest thousandth.

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  1. 15 January, 09:02
    0
    0.667

    Step-by-step explanation:

    Performing the indicated division gets you ...

    y = (2/3) + (32/3) / (3x^2 - 16)

    The term containing x goes to zero as x gets large, leaving y = 2/3 as the horizontal asymptote. In decimal form, this is approximately ...

    y = 0.667
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