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Jake Jackson
Mathematics
31 December, 12:34
How do you solve 3|x-2|-10=11
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Tess Graves
31 December, 12:51
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3|x - 2| - 10 = 11
3 (x - 2) - 10 = 11 U 3 (x - 2) + 10 = - 11
3 (x) - 3 (2) - 10 = 11 U 3 (x) - 3 (2) + 10 = - 11
3x - 6 - 10 = 11 U 3x - 6 + 10 = - 11
3x - 16 = 11 U 3x + 4 = - 11
3x - 16 + 16 = 11 + 16 3x + 4 - 4 = - 11 - 4
3x = 27 U 3x = - 15
3 3 3 3
x = 9 U x = - 5
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