Angle N = 40 degrees, side NP = 8, angle Q = 40 degrees, and side QS = 8. What additional information would you need to prove that ΔNOP ≅ ΔQRS by ASA?.

For A S A : if 2 angles and the included side of triangle are congruent to 2 angles and the included side of another triangle, then the two triangles are comgruent.

We have : NP = QS and ∠N = ∠Q. Therefore, we need another angle: ∠P must be equal to ∠S

Answer: B) Angle P is congruent to angle S.