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Kamari
Mathematics
27 November, 17:53
Find dy/dx by implicit differentiation xy=6
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Elisha Prince
27 November, 17:56
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dy/dx = - y/x
Step-by-step explanation:
xy = 6
x * dy + y * dx = 0
Subtract y dx from each side
x dy = - y dx
Divide each side by dx
x dy / dx = - y dx/dx
x dy/dx = - y
Divide by x
dy/dx = - y/x
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Berger
27 November, 17:59
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Step-by-step explanation:
Apply the derivative operator d/dx to xy = 6. xy is a product, so we must use the product rule as well as the chain rule.
dy/dx = - y/x
(d/dx) (xy = 6) works out to x (dy/dx) + y (dx/dx) = 0, or just x (dy/dx) + y = 0.
Solving this for dy/dx, we get, first, x (dy/dx) = - y, and then
dy/dx = - y/x
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