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12 July, 11:06

A function f is periodic of period of period 5. If f (3) = 10, f (0) = 13, and f (-5) = 31 then find f (13)

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  1. 12 July, 11:25
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    If f (x) is some function with period T, then f (x) = f (x+T) for all x in the domain.

    In this case, T = 5 is the period so

    f (x) = f (x+5)

    f (3) = 10

    f (3) = f (3+5) = f (8) = 10

    f (8) = f (8+5) = f (13) = 10

    Therefore, f (13) = 10

    The final answer is 10
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