A restaurant serves 3 kinds of pasta, 5 kinds of sauces, and 4 side dishes. The number of different

meals that include 1 pasta, 1 sauce, and 1 side dish is 3 x 5 x 4 = 60. If they stop serving one type of

side dish, how many different meals are possible?

A) 11

B) 24

C) 45

D) 59

Question

Brice

Mathematics

30 April, 14:06

A restaurant serves 3 kinds of pasta, 5 kinds of sauces, and 4 side dishes. The number of different

meals that include 1 pasta, 1 sauce, and 1 side dish is 3 x 5 x 4 = 60. If they stop serving one type of

side dish, how many different meals are possible?

A) 11

B) 24

C) 45

D) 59

+4

Answers (2)

Know the Answer?

Layton Ford · Answer 1

Pretty sure your answer would be (b) 24

Jesse Jordan · Answer 2

C) 45

Step-by-step explanation:

Your answer would be 45 since we got rid of one side dish which will leave you with 3. So the equation 3x5x4=60 will become 3x5x3 which equals 45.

A restaurant serves 3 kinds of pasta, 5 kinds of sauces, and 4 side dishes. The number of differentmeals that include 1 pasta, 1 sauce, and 1 side dish is 3 x 5 x 4 = 60. If they stop serving one type ofside dish, how many different meals are possible?A) 11B) 24C) 45D) 59

A restaurant serves 3 kinds of pasta, 5 kinds of sauces, and 4 side dishes. The number of different

meals that include 1 pasta, 1 sauce, and 1 side dish is 3 x 5 x 4 = 60. If they stop serving one type of

side dish, how many different meals are possible?

A) 11

B) 24

C) 45

D) 59