A football player completes a pass 69.4 % of the time. Find the probability that (a) the first pass he completes is the second pass, (b) the first pass he completes is the first or second pass, and (c) he does not complete his first two passes.

Step-by-step explanation:

(a) If his second pass is the first that he completes, that means he doesn't complete his first pass.

P = P (not first) * P (second)

P = (1 - 0.694) (0.694)

P ≈ 0.212

(b) This time we're looking for the probability that he doesn't complete the first but does complete the second, or completes the first and not the second.

P = P (not first) * P (second) + P (first) * P (not second)

P = (1 - 0.694) (0.694) + (0.694) (1 - 0.694)

P ≈ 0.425

(c) Finally, we want the probability he doesn't complete either pass.

P = P (not first) * P (not second)

P = (1 - 0.694) (1 - 0.694)

P ≈ 0.094