Ms. Johnson asked her class to write an equivalent expression to

14d - 9 + 21k - 7dk + 2

• Riley wrote the expression

7dk (2 - 3 - 1) - 7

• Ahmad wrote the expression

7 (2d - 3k - dk) - 7

• Ariana wrote the expression

7k (2d - 3 - d) - 7

Who us correct? Explain how you know.

Question

Karissa Fritz

Mathematics

22 December, 14:28

Ms. Johnson asked her class to write an equivalent expression to

14d - 9 + 21k - 7dk + 2

• Riley wrote the expression

7dk (2 - 3 - 1) - 7

• Ahmad wrote the expression

7 (2d - 3k - dk) - 7

• Ariana wrote the expression

7k (2d - 3 - d) - 7

Who us correct? Explain how you know.

+1

Answers (1)

Know the Answer?

Rachael Marks · Answer 1

No one got the correct answer. The answer is supposed to be 7 (2d+3k-dk-1). All the coefficients are divisible by 7, thus only the integers are changed. However, the variables cannot be a factor because they do not have the same variables that all the coefficients must have.

Ms. Johnson asked her class to write an equivalent expression to14d - 9 + 21k - 7dk + 2• Riley wrote the expression7dk (2 - 3 - 1) - 7• Ahmad wrote the expression7 (2d - 3k - dk) - 7• Ariana wrote the expression7k (2d - 3 - d) - 7Who us correct? Explain how you know.

Ms. Johnson asked her class to write an equivalent expression to

14d - 9 + 21k - 7dk + 2

• Riley wrote the expression

7dk (2 - 3 - 1) - 7

• Ahmad wrote the expression

7 (2d - 3k - dk) - 7

• Ariana wrote the expression

7k (2d - 3 - d) - 7

Who us correct? Explain how you know.