Ask Question
2 April, 03:16

Jennifer went to the post office for stamps. She bought the same number of 8-cent stamps and 10-cent stamps. She also bought as many 2-cent stamps as both of the other two kinds combined. How many of each kind did she get if she paid a total of $4.40 for them all?

+4
Answers (1)
  1. 2 April, 03:35
    0
    E=number of eight cent stamps

    t=number of ten cent stamps bought

    w=number of 2 cent stamps bought

    number of eight=number of ten

    e=t

    as many 2 cent as the other 2 combined

    e+t=w or

    2e=w=2t

    total she bouthgt 4.40

    4.40=440 cents

    8e+10t+2w=440

    solve for t or e, I solve for t

    8t+10t+2 (2t) = 440

    18t+4t=440

    22t=440

    divide 22

    t=20

    t=e

    20=e

    w=2e

    w=2 (20)

    w=40

    answer is

    20 eight cent

    20 ten cent

    40 two cent
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Jennifer went to the post office for stamps. She bought the same number of 8-cent stamps and 10-cent stamps. She also bought as many 2-cent ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers