Jennifer went to the post office for stamps. She bought the same number of 8-cent stamps and 10-cent stamps. She also bought as many 2-cent stamps as both of the other two kinds combined. How many of each kind did she get if she paid a total of $4.40 for them all?

Question

Alisa Bauer

Mathematics

2 April, 03:16

Jennifer went to the post office for stamps. She bought the same number of 8-cent stamps and 10-cent stamps. She also bought as many 2-cent stamps as both of the other two kinds combined. How many of each kind did she get if she paid a total of $4.40 for them all?

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Answers (1)

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Kimberly Costa · Answer 1

E=number of eight cent stamps

t=number of ten cent stamps bought

w=number of 2 cent stamps bought

number of eight=number of ten

e=t

as many 2 cent as the other 2 combined

e+t=w or

2e=w=2t

total she bouthgt 4.40

4.40=440 cents

8e+10t+2w=440

solve for t or e, I solve for t

8t+10t+2 (2t) = 440

18t+4t=440

22t=440

divide 22

t=20

t=e

20=e

w=2e

w=2 (20)

w=40

answer is

20 eight cent

20 ten cent

40 two cent