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21 November, 17:36

Measured distance: 84ft

actual distance: 80ft

percent error:?

+5
Answers (2)
  1. 21 November, 17:49
    0
    Per enrage error is 5%
  2. 21 November, 17:49
    0
    1. Subtract the actual distance from the measured distance to find the error:

    80-84 = - 4 (just ignore the negative sign) so our error is 4

    2. Divide error by the actual distance:

    4/80 = 0.05

    3. Multiply that by 100 to find percent:

    .05*100 = 5%

    Percentage error is 5%
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