The rectangle shown has a perimeter of 58 cm and the given area. Its

length is 4 more than four times its width. Write and solve a system of

equations to find the dimensions of the rectangle.

The length of the rectangle is_cm and the width of the rectangle is _cm.

Answer:width=5cm length=24cm

Step-by-step explanation:

Width=w

Length=L

Perimeter = 58

Perimeter=2L+2w

2L+2w=58

There length is 4 more than 4 times it width

L-4=4w

L=4w+4

Substitute L=4w+4 in 2L+2w=58

2 (4w+4) + 2w=58

8w+8+2w=58

Collect like terms

8w+2w=58-8

10w=50

Divide both sides by 10

10w/10=50/10

w=5 width is 5cm

Substitute w=5 in 2L+2w=58

2L+2 (5) = 58

2L+10=58

2L=58-10

2L=48

Divide both sides by 2

2L/2=48/2

L=24 length=24cm