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11 March, 07:54

The equation h (t) = - 16 t 2 + 19t+110 gives the height of a rock, in feet, t seconds after it is thrown from a cliff. What is the initial velocity when the rock is thrown? Enter your answer in the box.

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  1. 11 March, 08:11
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    For this case we have an equation of the form:

    h (t) = (1/2) * a * t ^ 2 + vo * t + h0

    Where,

    a: acceleration

    vo: initial speed

    h0: initial height

    t: time

    We have then that the equations:

    h (t) = - 16t ^ 2 + 19t + 110

    Therefore, the initial velocity is given by:

    vo = 19 feet / s

    Answer:

    The initial velocity when the rock is thrown is:

    vo = 19 feet / s
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