A vase contains 4 pink roses, 8 red roses, and 10 white roses. Two roses are randomly selected from the vase one at a time, without replacement. What is the probability that both roses selected are red?

1. 14/121

2. 4/33

3. 32/231

4. 35/231

Question

Tori Glenn

Mathematics

16 September, 23:52

A vase contains 4 pink roses, 8 red roses, and 10 white roses. Two roses are randomly selected from the vase one at a time, without replacement. What is the probability that both roses selected are red?

1. 14/121

2. 4/33

3. 32/231

4. 35/231

+5

Answers (1)

Know the Answer?

Gabriela Michael · Answer 1

There are 22 roses in the vase

probability of first selecting a red rose = 8/22 = 4/11

P (second one is red) = 7/21 = 1/3

these probabilities are multiplied because the individual picks are independent

so the answer is 4/11 * 1/4 = 4/33

A vase contains 4 pink roses, 8 red roses, and 10 white roses. Two roses are randomly selected from the vase one at a time, without replacement. What is the probability that both roses selected are red?1. 14/1212. 4/333. 32/2314. 35/231

A vase contains 4 pink roses, 8 red roses, and 10 white roses. Two roses are randomly selected from the vase one at a time, without replacement. What is the probability that both roses selected are red?

1. 14/121

2. 4/33

3. 32/231

4. 35/231