Solve 2^x=32 and rewrite this equation in a logarithmic form

x=5

x = log2 (32)

Step-by-step explanation:

2^x=32

Rewrite 32 as 2^5

2^x = 2^5

Since the bases are the same, the exponents have to be the same

x=5

2^x=32

Take log base 2 on each side

log2 (2^x) = log2 (32)

x = log2 (32)