3r (2p-5) - p (2p-5) factorise it

Question

Alexis Pruitt

Mathematics

4 October, 07:04

3r (2p-5) - p (2p-5) factorise it

+5

Answers (2)

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Xzavier Whitaker · Answer 1

3r (2p - 5) - p (2p - 5)

let a = 2p - 5

3r (2p - 5) - p (2p - 5) = 3ra - pa = a (3r - p)

let's substitute back the value of a.

a (3r - p) = (2p - 5) (3r - p)

Therefore: 3r (2p - 5) - p (2p - 5) = (2p - 5) (3r - p)

Wilkerson · Answer 2

3r (2p - 5) - p (2p - 5)

The common factor is (2p - 5), therefore we can write:

(2p - 5) (3r - p)