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7 October, 02:59

If f (1) = 160 and f (n + 1) = - 2f (n), what is f (4) ?

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  1. 7 October, 03:21
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    f (1) = 160

    f (2) = f (1+1) = - 2f (1)

    f (3) = f (2+1) = - 2f (2) = (-2) · (-2) f (1) = 4f (1)

    f (4) = f (3+1) = - 2f (3) = - 2·4f (1) = - 8f (1) = - 8·160 =
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