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14 October, 05:09

Write a formula to describe the sequence

1, 0.9, 0.8, 0.7, 0.6, 0.5 ...

A. A (n) = 1 - A (n - 1)

B. A (n) = n - 0.1 (n - 1)

C. A (n) = 1 - 0.1n

D. A (n) = 1 - 0.1 (n - 1)

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Answers (1)
  1. 14 October, 05:33
    0
    d

    Step-by-step explanation:

    A (n) = 1 - 0.1 (n-1)

    A (1) = 1 - 0.1 * (1-1) = 1 - 0.1*0 = 1

    A (2) = 1 - 0.1 * (2-1) = 1 - 0.1*1 = 1 - 0.1 = 0.9

    A (3) = 1 - 0.1 (3-1) = 1 - 0.1*2 = 1-0.2=0.8

    Method:

    A (1) = 1

    D = A (2) - A (1) = 0.9 - 1 = - 0.1

    A (n) = A (1) + (n-1) * d = 1 + (n-1) * (-0.1)

    = 1 - 0.1 (n - 1)
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