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13 August, 00:42

How do you find the y-intercept for x = 2y2 + 3y + 1

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  1. 13 August, 00:52
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    The y intercept is when x=0. That's solving the quadratic

    0 = 2y² + 3y + 1 = (2y + 1) (y + 1)

    y = - 1 or 2y+1=0 so y=-1/2

    Two y intercepts, (0,-1) and (0,-1/2)

    Answer: - 1 and - 1/2
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