Differentiate the function F (t) = ln [ (2t+1) ^3 / (3t-1) ^4]

Hi, ok. Let me explain you:

Firstly, we have:

f - 1 (f (x)) = f (f - 1 (x)) = x

We' are going to use this to find f - 1 (x)

then f (x) = 5x-3

to find f - 1 (x)

so, we put x = f - 1 (x),

and we havef (f-1 (x)) = 5f-1 (x) - 3

thus, we get x=5f-1 (x) - 3 5 f - 1 (x) = x+3 or maybe f - 1 (x) = x+3 5