Ask Question
24 June, 14:03

Jake is planning a trip to China. He has made a list of cities he would like to visit, as well as the approximate amount of money he plans to spend in each as a result of travel, lodging, shopping, and so on. All costs are listed in renminbi (¥).

City

Cost (¥)

Tianjin

557

Nanjing

681

Zhengzhou

595

Beijing

728

Wuhan

449

Chengdu

534

Unfortunately, Jake only has ¥2,920 available. What is the cheapest city that Jake can remove from his travel plans and still stay under budget?

a.

Tianjin

b.

Wuhan

c.

Nanjing

d.

Beijing

+5
Answers (1)
  1. 24 June, 14:17
    0
    The answer is D, because when you add them all together then you will get 3,544 the subtract 728 and that gives you 2816 and that's under Jake's budget
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Jake is planning a trip to China. He has made a list of cities he would like to visit, as well as the approximate amount of money he plans ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers