Herky was given the following system of equations to solve.

3x-2y=17

x-3y=1

What is the solution to the system?

(2,7)

(20/7,67/7)

(7,2)

(67/7,20/7)

Option 3 (7,2) is right answer.

Step-by-step explanation:

Given two equations

3x-2y=17 ... i

x-3y=1 ... ii

We can solve this by elimination.

coefficients of x are 3 and 1 with LCD = 3

Hence multiply ii equation by 3

3x-9y = 3 ... iv

3x-2y = 17 ... i

Subtract i from iv

-7y = - 14

Divide by - 7

y = 2

Substitute in ii

x-3 (2) = 1

x=7

Hence solution is (7,2)

Verify:

We can verify our solution by substituting in i and ii.

3 (7) - 2 (2) = 17 and 7-6 = 1

Verified

Answer: C