The sum of three numbers is 141. The first number is 9 more than the third. The second number is 4 times the third. What are the numbers?

x ... third number

4x ... second number

x-9 ... first number

(x) + (4x) + (x-9) = 141

x+4x+x-9=141

6x-9=141

Let's add 9 to both sides ...

9+6x-9=141+9

6x=150

Let's divide both sides by 6 ...

(6x) / 6=150/6

x=25

third number ... 25

second number ... (4) (25) = 100

first number ... (25-9) = 16

Let's check our work ...

25+100+16=141

141=141