The equation of a parabola is shown.

x-7=3/4y^2

What are the coordinates of the focus?

A.) (71/3,0)

B.) (7,-1/3)

C.) 73/4,0)

D.) 7,-3/4)

The axis of symmetry for this parabola is the x-axis. The general form of the equation is:

4p (x-h) = (y-k) ^2

where the focus has the coordinates of (h+p, k)

Manipulating the given equation to the general form:

4 (1/3) (x-7) ^2 = (y - 0) ^2

Therefore the coordinates of the focus is:

(7 + (1/3),0)

The answer is A.) (71/3,0)