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16 April, 08:32

What is the perimeter, P, of a rectangle that has a length of x + 6 and a width of y - 1?

P = x + y + 5

P = x + y - 7

P = 2x + 2y + 10

P=2x + 2y - 10

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Answers (2)
  1. 16 April, 08:41
    0
    just took the test the answer is P = 2x + 2y + 10
  2. 16 April, 08:52
    0
    Answer: P = 2x + 2y + 10

    Step-by-step explanation: The perimeter (P) of a rectangle is given as

    P = 2L + 2W

    By factorizing the right hand side of the equation we now have

    P = 2 (L + W)

    However, the length of the rectangle is given as x + 6 and the width is given as y - 1

    If P = 2 (L + W), then

    P = 2 (x + 6 + {y - 1})

    P = 2 (x + 6 + y - 1)

    P = 2 (x + y + 5)

    After expanding the bracket, we now have

    P = 2x + 2y + 10
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