A stadium has 50,000 seats. Seats in section A cost $30, seats in section B cost $24, and seats in section C cost $18. the number of seats in section A is equal to the total number of seats in section B and C. Suppose the stadium takes in $1,287,600 from each sold out event. How many seats does each section have?

Section A = 25,000 seats

Section B = 14,600 seats

Section C = 10,400 seats

Step-by-step explanation:

Total Seats = 50,000

Seats in Section A cost = $30

Seats in Section B cost = $24

Seats in Section C cost = $18

Total sales from the event = $1,287,600

No. of Seats in section A = No. seats in Section B + No. seats in Section C

A = B + C

or, 2A = 50,000

A = 25,000 seats @ $30/seat = $750,000

B + C = 25,000

24B + 18C = 537,600

24B + 18 (25,000 - B) = 537,600

24B + 450,000 - 18B = 537,600

6B = 87600

B = 14,600

C = 10,400

Hence;

A = 25,000 seats

B = 14,600 seats

C = 10,400 seats