Write the quadratic function in vertex form.

y = x2 - 2x + 5

y = (x + 1) 2 - 4

y = (x - 1) 2 - 4

y = (x + 1) 2 + 4

y = (x - 1) 2 + 4

I think the answer would look something like this Y-4 = (x-1) ^2

The answer to your question is y = (x - 1) ² + 4

Step-by-step explanation:

y = x² - 2x + 5

Complete perfect square trinomial

y - 5 = x² - 2x

y - 5 + () ² = x² - 2x + () ²

y - 5 + (1) ² = x² - 2x + (1) ²

y - 5 + 1 = x² - 2x + 1

Factor and simplify y - 4 = (x - 1) ²

y = (x - 2) ² + 4