Suppose that 43% of all adults in a certain community are obese and that 36% suffer from diabetes. If 20% of the adults in this community are both obese and suffering from diabetes, what is the probability that a randomly chosen adult in this community is obese or suffers from diabetes (or both) ? Write your answer as a decimal (not as a percentage)

Question

Danica Rivers

Mathematics

3 September, 08:26

Suppose that 43% of all adults in a certain community are obese and that 36% suffer from diabetes. If 20% of the adults in this community are both obese and suffering from diabetes, what is the probability that a randomly chosen adult in this community is obese or suffers from diabetes (or both) ? Write your answer as a decimal (not as a percentage)

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Answers (1)

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Andrew Cobb · Answer 1

0.59

Step-by-step explanation:

Since the probability of adults in this community that are both obese and suffering from diabetes overlap, when you add 43% and 36%, you count the percentage that overlap twice (Once the obese adults and once for the diabetic adults). Therefore, you have to subtract 20% from 43% + 36% so you only count the overlap once. Solving, 43% + 36% - 20% = 59%, or 0.59.