The position of a particle as it moves along the x axis is given for t>0 by x = (t^3 - 3t^2 + 6t) m, where t in sec. Where id the particle wen it achieves its minimum speed (after t=0) ?

Question

Davon

Mathematics

17 May, 14:19

The position of a particle as it moves along the x axis is given for t>0 by x = (t^3 - 3t^2 + 6t) m, where t in sec. Where id the particle wen it achieves its minimum speed (after t=0) ?

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Leonidas Wilkinson · Answer 1

We are given with the equation of the distance of a particle expressed in x = (t^3 - 3t^2 - 6t). To get the distance where minimum speed is achieved, we get the first derivative of the equation and equate to zero. hence, dx / dt = 3t^2 - 6t - 6 = 0. t is equal to 2.73 sec. The distance then after substituting to the original equation equal to 14.37 meters.