The polynomial 0.0012 x cubed minus 0.075 x squared plus 1.6 x plus 13 0.0012x3-0.075x2+1.6x+13 models natural gas consumption in trillions of cubic feet, where x equals = 0 corresponds to 1960, x equals = 1 to 1961, and so on. How much natural gas was consumed in 1990?

Step-by-step explanation:

Given:

Equation

natural gas consumption in trillions of cubic feet, Nc = 0.0012x^3 - 0.075x^2 + 1.6x + 13

At x = 0 in 1960,

Nc = 13 trillions ft^3

Therefore,

x = current year - reference year

= 1990 - 1960

= 30

Nc = 0.0012x^3 - 0.075x^2 + 1.6x + 13

Inputting x = 30,

Nc = 0.0012 * (30) ^3 - 0.075 * (30) ^2 + 1.6 * (30) + 13

= 25.9 trillion ft^3

= 2.59 * 10^13 ft^3

25.9 Trillions Cubic feet

Step-by-step explanation:

The polynomial that models consumption of natural gas is given as 0.0012x³-0.075x²+1.6x+13

x=0 (In 1960)

x=1 (In 1961)

Therefore in 1990, x=1990-1960=30

We substitute x=30 in the polynomial to determine gas consumption in 1990.

0.0012x³-0.075x²+1.6x+13

Consumption in 1990

=0.0012 (30) ³-0.075 (30) ²+1.6 (30) + 13

= (0.0012 X 27000) - (0.075 X 900) + 48 + 13

=32.4-67.5+48+13

=25.9

Therefore, in 1990, 25.9 Trillions Cubic feet of gas was consumed.