Sydney bought 5.65 lbs of roast beef, which was on sale for $4.50 per pound. if she divides the roast beef evenly among 6.5, how much was the cost per sandwich?

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Mathematics

26 May, 09:10

Sydney bought 5.65 lbs of roast beef, which was on sale for $4.50 per pound. if she divides the roast beef evenly among 6.5, how much was the cost per sandwich?

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Gloria Hunt · Answer 1

Okay. So, she buoyant 5.65 lbs of roast beef for $4.50. Multiply both of those numbers to get 25.425 or 25.43 when rounded to the nearest hundredth. So the total cost was $25.43. However, we now have to divide the amount by 6.5. 25.43/6.5 is 3.912 and other odd numbers or 3.91 when rounded to the nearest hundredth. The cost per sandwich was $3.91.