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Rex Mckee
Mathematics
5 July, 08:01
how to integrate a/1-ay?
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Lilia Manning
5 July, 08:14
0
In private correspondence with the author of the question, it was determined
that 'y' is the variable of integration.
Therefore, 'a' is a constant for purposes of this integration, and that whole
'a' business can be taken outside the integral.
Integral [a / (1-ay) dy] = a / (1-a) integral [dy/y] = a ln (y) / (1-a) + C
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