Mathematics

17 April, 19:47

From the top of a vertical tower 248 m high, a stone is projected vertically downwards with a speed of 8 ms. After x seconds another stone is projected vertically upwards from the level of the base of the tower with a speed 25 ms. Given that two stones are at same height moving in the same direction 6 seconds after projection of the first stone, calculate:

1) value of x

2) the velocity of the second stone at this instant

+5

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