Assume that a researcher randomly selects 14 newborn babies and counts the number of girlsâ selected, x. the probabilities corresponding to the 14 possible values of x are summarized in the given table. find the probability of selecting 9 or more girls.

Probability is the mathematics of chance. In other words, it is the fraction or percentage of a certain event successfully happening. For this problem, you want to determine the probability of selecting 9, 10, 11, 12, 13 or 14 girls. The solution is as follows:

P = nCr p^r q^n-r

where

n is number of total events (n = 14)

r is the number of events that could happen (9, 10, 11, 12,13 and 14)

p is the probability of an event being a girl (p = 50% or 0.5)

q is the probability of either an event being a boy (q = 1-p = 0.5)

nCr is a combination formula which is n! / (r! (n-r) !)

P = [14C9 * (.5) ^9 * (0.5) ^5] + [14C10 * (.5) ^10 * (0.5) ^4]+[14C11 * (.5) ^11 * (0.5) ^3]+[14C12 * (.5) ^12 * (0.5) ^2]+[14C13 * (.5) ^13 * (0.5) ^1]+[14C14 * (.5) ^14 * (0.5) ^0]

P = 0.211 or 21.1%