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30 May, 06:35

13. A rectangle has a width that is twice as long as its length and an area of 722 square inches. Find the length of the diagonal, rounded to the nearest tenth.

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  1. 30 May, 06:56
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    The diagonal of the rectangle is approximately 42.5 inches.

    Step-by-step explanation:

    The area of a rectangle is given by the following formula:

    area = width*length

    In this case the width = 2*length, therefore we have:

    area = 2*length²

    722 = 2*length²

    2*length² = 722

    length² = 361

    length = sqrt (361) = 19 inches

    width = 2*length = 2*19 = 38 inches

    The diagonal forms a right triangle with the sides of the rectangle, where it is the hypotenuse. Therefore we can use Pytagora's theorem:

    diagonal = sqrt (length² + width²)

    diagonal = sqrt (19² + 38²) = 42.485 inches

    The diagonal of the rectangle is approximately 42.5 inches.
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