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Find two consecutive integers such that the sum of the first and twice the second is 74

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  1. 31 May, 21:46
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    Let the consecutive integers be x and x+1

    x+2 (x+1) = 74

    or x+2x+2=74

    3x=74-2=72

    x=72/3=24

    x+1=24+1=25

    hence numbers are 24 and 25
  2. 31 May, 22:07
    0
    Consecutive integers are 1 apart

    they are x and x+1

    sum of firt and twice the 2nd is 74

    sum is addition

    twice is 2 times

    x+2 (x+1) = 74

    distribute

    x+2x+2=74

    add like terms

    3x+2=74

    minus 2 both sides

    3x=72

    divide both sides by 3

    x=24

    x+1=25

    the numbers are 24 and 25
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