Area of a square with a length of 20x minus the area of a circle with a radius of 4x

Question

Walker Castaneda

Mathematics

23 January, 19:21

Area of a square with a length of 20x minus the area of a circle with a radius of 4x

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Answers (2)

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Macey Schwartz · Answer 1

Area of squre=legnth times legnth so area of square = (20x) ^2=400x^2 area of circle=pi times r^2 pi times (4x) ^2 pi times 16x^2 aprox 50.27x^2 so 400x^2-50.27x^2=349.73x^2

Kendal Carson · Answer 2

Area of the square = (20x) ²

Area of the circle = πr² = π (4x) ²

(20x) ² = 20x * 20x = 400x²

π * (4x) ² = 16x²π

Total area = (400x²) - 16x²π

Total area = x² (400 - 16π)

Total area = x² 16 * (25 - π)

Total area = 16x² (25 - π)