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10 January, 20:24

How do I solve for x:

2 (x-5) ^2+13=31

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Answers (1)
  1. 10 January, 20:35
    0
    2 (x - 5) ² + 13 = 31

    2 (x - 5) (x - 5) + 13 = 21

    2 (x (x - 5) - 5 (x - 5)) + 13 = 21

    2 (x (x) - x (5) - 5 (x) + 5 (5)) + 13 = 21

    2 (x² - 5x - 5x + 25) + 13 = 21

    2 (x² - 10x + 25) + 13 = 21

    2 (x²) - 2 (10x) + 2 (25) + 13 = 21

    2x² - 20x + 50 + 13 = 21

    2x² - 20x + 63 = 21

    - 21 - 21

    2x² - 20x + 42 = 0

    2 (x²) - 2 (20x) + 2 (21) = 0

    2 (x² - 20x + 21) = 0

    2 2

    x² - 20x + 21 = 0

    x = - (-20) + / - √ ((-20) ² - 4 (1) (21))

    2 (1)

    x = 20 + / - √ (400 - 84)

    2

    x = 20 + / - √ (316)

    2

    x = 20 + / - 2√ (79)

    2

    x = 10 + √ (79)

    x = 10 + √ (79) U x = 10 - √ (79)
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