The length of a rectangle is 2 more than 3 times the width. If the perimeter is 100, find the length and width of the rectangle.

If l = length and w = width, which of the following systems could be used to solve the problem?

L=17.49635531

W=5.715476066

100 = L X W

L = 2 + 3W

Insert the L equation into the 1st equation, 2 + 3W x W = 100

2 + 3W x W = 100

-2 - 2

3W X W = 98

3W^2 = 98

Divide both sides by 3

W^2 = 32.66

Square root both sides

now you have the Width, plug the width into the L X W = 100 equation, then divide 100 by the width, and now you have the length.