The area of each triangular base is: A = 1/2 (b) (h) A = 1/2 (4) (3) A = in. 2 There are two bases, so total base area is in. 2. The lateral area is: A = 8 (4) + 8 (3) + 8 (5) A = in. 2 The total surface area is in. 2.

6 in^2

12 in^2

96 in^2

AT = 108 in^2

Step-by-step explanation:

The area of one triangular face is

A1 = 1/2 (4) (3) = 6 in^2

The area of the two triangular faces is:

A = 2A1 = 12 in^2

the area of the lateral faces is:

Al = 8 (4) + 8 (3) + 8 (5) = 96 in^2

Hence, the total surface area is

AT = At + Al = 12 in^2 + 96 in^2 = 108 in^2