A cash register at a store contains $227 bills. There are six more $5 bills than $10 bills. The number of $1 bills is two more than 24 times the number of $10 bills. How many bills of each kind are there?

Take the amount of $10 bills as x

n. o. of $5 bills = x+6

n. o. of $1 bills = 24x+2

value of $10 bills = 10x

value of $5 bills = 5x+30

value of $1 bills = 24x+2

total value = 24x+2+5x+30+10x = 39x + 32

39x+32=227

39x=195

x=5

there are 5 $10 bills, 11 $5 bills and 122 $1 bills