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Jaxson Swanson
Mathematics
7 January, 03:15
Find dy/dx if y = (cos x) ^ x
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Mikayla Friedman
7 January, 03:33
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Y = (cos x) ^x
log y = log (cos x) ^x = x log (cos x)
1/y dy/dx = x * 1/cos x * - sin x + log (cos x) = - xsin x / cos x + log (cos x) = log (cos x) - xtan x
dy/dx = y (log (cos x) - xtan x) = (cos x) ^x (log (cos x) - xtan x)
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