What are three consecutive positive integers with a sum of 120

Question

Stein

Mathematics

24 July, 03:50

What are three consecutive positive integers with a sum of 120

+3

Answers (2)

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Evangeline Lambert · Answer 1

Consetuve integers are 1 apart

they are n, n+1, n+2

so

n+n+1+n+2=120

3n+3=120

miknus 3 both sides

3n=117

divide both sides by 3

n=39

n+1=40

n+2=41

the numbers are 39,40,41

Christine Cabrera · Answer 2

Consecutive numbers are numbers right next to each other like 1 2 3 so I think you'd divide 120 by 3. But I think the numbers are 39 40 and 41