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Bianca Moyer
Mathematics
2 January, 18:32
3|x-1| > = 12
A. X> = - 3 or x< = 5
B. X = 5
C. X> = 5
D. X=5
+4
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Izayah Weber
2 January, 18:52
0
3|x-1| ≥ 12
|x-1| ≥ 4. Remove the absolute signs:
x - 1 ≥ 4 → x≥ 5
and x-1 ≤ - 4 → x≤ - 3
Then D. x ≤ - 3 or x ≥ 5
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