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23 December, 12:16

Function f has f (10) = 20, f′ (10) = 2 and f′′ (x) <0, for x≥10. Which of the following are possible values for f (14) ?

f (14) = 20.28 is

f (14) = 20.14 is

f (14) = 20.56 is

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Answers (1)
  1. 23 December, 12:46
    0
    f (14) = 28

    Step-by-step explanation:

    The function that satisfy the equations is

    f (x) = 3x - x

    f (10) = 3*10 - 10 = 30 - 10 = 20

    f' (x) = 3 - 1 = 2.

    Therefore,

    f (14) = 3 (14) - 14 = 42 - 14 = 28.

    f (14) = 28
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